${\tan ^{ - 1}}\left[ {\frac{{\sqrt {1 + {x^2}} + \sqrt {1 - {x^2}} }}{{\sqrt {1 + {x^2}} - \sqrt {1 - {x^2}} }}} \right]$,જ્યાં $|x| < 1$ અને $x \ne 0$ હોય,તેની કિંમત શું થાય?

  • A
    $\frac{\pi }{4} + \frac{1}{2}{\cos ^{ - 1}}{x^2}$
  • B
    $\frac{\pi }{4} + {\cos ^{ - 1}}{x^2}$
  • C
    $\frac{\pi }{4} - \frac{1}{2}{\cos ^{ - 1}}{x^2}$
  • D
    $\frac{\pi }{4} - {\cos ^{ - 1}}{x^2}$

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$x$ ની કિંમત શોધો જેથી $\sin \left(2 \tan ^{-1} \frac{3}{4}\right)=\cos \left(2 \tan ^{-1} x\right)$ થાય.

કિંમત શોધો: $\cos ^{-1}\left(\frac{4}{5}\right)+\cos ^{-1}\left(\frac{12}{13}\right)$

જો $\log_{\pi}x > 0$ હોય,તો $\log_{\pi}\left( \sin^{-1}\frac{2x}{1+x^2} + 2\tan^{-1}x \right)$ ની કિંમત કેટલી થાય?

જો $x \in \left(0, \frac{1}{4}\right)$ માટે,$\tan^{-1}\left(\frac{6x\sqrt{x}}{1-9x^3}\right)$ નું વિકલન $\sqrt{x} \cdot g(x)$ હોય,તો $g(x)$ ની કિંમત શોધો.

$\tan ^{-1}(1)+\cos ^{-1}\left(-\frac{1}{2}\right)+\sin ^{-1}\left(-\frac{1}{2}\right)$ નું મૂલ્ય શોધો.

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